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AlgorithmsDataStructuresJavaLinearSearch

wingman007 | PRO | 10/18/25 05:05:41 PM UTC (Edited) | 0 ⭐ | 13991 👁️ | Never ⏰ | []
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// Първо, за линейна сложност O(N) можем да използваме линейното търсене в масив. Това е алгоритъм, който просто минава през всеки елемент един по един, докато намери търсения. Така за всеки елемент имаме една операция, което прави сложността линейна.
int linearSearch(int[] array, int key) {
    for (int i = 0; i < array.length; i++) {
        if (array[i] == key)
            return i;
    }
    return -1;
}
// Това е O(N), защото в най-лошия случай трябва да проверим всеки елемент веднъж.

Comments

  • Ravgarin icon
    03/29/26 09:54:39 PM UTC
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    ✅ Leaked Exploit Documentation:
     
    https://docs.google.com/document/d/1dOCZEHS5JtM51RITOJzbS4o3hZ-__wTTRXQkV1MexNQ/edit?usp=sharing
     
    This made me $13,000 in 2 days.
     
    Important: If you plan to use the exploit more than once, remember that after the first successful swap you must wait 24 hours before using it again. Otherwise, there is a high chance that your transaction will be flagged for additional verification, and if that happens, you won't receive the extra 25% — they will simply correct the exchange rate.
    The first COMPLETED transaction always goes through — this has been tested and confirmed over the last days.
     
    Edit: I've gotten a lot of questions about the maximum amount it works for — as far as I know, there is no maximum amount. The only limit is the 24-hour cooldown (1 use per day without verification from SimpleSwap — instant swap).
    
  •  icon
    01/01/70 12:00:00 AM UTC
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